Solved UPSC CDS/OTA Question
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Q · Time, Speed and DistanceMedium · 45s
A man walks from his house to the office at 5 km/hr, he reaches the office 10 minutes later than the scheduled time. However, if he walks 1 km/hr more than the previous speed he reaches 10 minutes earlier than the scheduled time. What is the distance between his house?
TopicTime, Speed and Distance
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min
Step-by-Step Solution
The complete worked solution.
Every step explained - no skipped algebra.
Time taken at 5 km/hr = x / 5
Time taken at 6 km/hr = x / 6
Difference = 20 minutes = 1/3 hour
So:
x/5 − x/6 = 1/3
→ (6x − 5x)/30 = 1/3
→ x/30 = 1/3
→ x = 10 km
Final Answer: Option A - 10 km