Solved UPSC CDS/OTA Question
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Q · OscillationMedium · 45s
A particle in SHM has a maximum speed vmax. What is its speed when the displacement is half the amplitude?
TopicOscillation
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min
Step-by-Step Solution
The complete worked solution.
Every step explained - no skipped algebra.
v=ωA₂−x₂v=ωA₂−x₂. For x=A/2x=A/2: v=vmax₁−(1/4)=vmax(3/2)v=vmax1−(1/4)=vmax(3/2).
Final Answer: Option A - 3/2vmax₃/2vmax