Mensuration · UPSC CDS/OTA · Question 26 of 30

Mensuration – Question 26

Step-by-step solution. Mensuration for UPSC CDS/OTA.

Topic
Mensuration
Subject
Mathematics
Difficulty
Medium
Solve Time
45–60 sec

Solved UPSC CDS/OTA Question

A solved UPSC CDS/OTA PYQ — decoded step-by-step.

Solve it the standard way once — then learn the shortcut.

Q · Mensuration Medium · 45s

The height of a wall is six times its width and the length of the wall is seven times its height. If volume of the wall be 16128 cube m, its width is

TopicMensuration
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min

Step-by-Step Solution

The complete worked solution.

Every step explained — no skipped algebra.

Let width of a wall = X m

Given: height of a wall is six times its width

Therefore height = 6X m

Given: the length of the wall is seven times its height

Therefore length = 7(6X) = 42X m

Volume of the wall = Length × width × height

Hence; 16128 = 42X×X×6X

→ 252X₃ = 16128 → X₃ = 64

→ X = 4 m

Width of wall = 4m.

Final Answer: Option A — 5 m
Solve Question✦ Build Plan
Mensuration Question 26 – UPSC CDS/OTA