Heat and Thermodynamics · UPSC CDS/OTA · Question 9 of 30

Heat and Thermodynamics – Question 9

Step-by-step solution. Heat and Thermodynamics for UPSC CDS/OTA.

Topic
Heat and Thermodynamics
Subject
General Studies
Difficulty
Medium
Solve Time
45–60 sec

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Q · Heat and ThermodynamicsMedium · 45s

A heat engine absorbs 2000 J from the hot reservoir and rejects 1200 J to the sink. Its efficiency is:

TopicHeat and Thermodynamics
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min

Step-by-Step Solution

The complete worked solution.

Every step explained — no skipped algebra.

Efficiency η = (Q₁ - Q₂)/Q₁ = (2000-1200)/2000 = 0.4 = 40%.

Final Answer: Option B — 40%
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Heat and Thermodynamics Question 9 – UPSC CDS/OTA