Circular Motion · UPSC CDS/OTA · Question 16 of 30

Circular Motion – Question 16

Step-by-step solution. Circular Motion for UPSC CDS/OTA.

Topic
Circular Motion
Subject
General Studies
Difficulty
Medium
Solve Time
45–60 sec

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Q · Circular MotionMedium · 45s

If a particle completes 2 revolutions per second, its angular speed is:

TopicCircular Motion
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min

Step-by-Step Solution

The complete worked solution.

Every step explained — no skipped algebra.

Angular speed ω = 2π × frequency = 2π × 2 = 4π rad/s.

Final Answer: Option C — 4π rad/s
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Circular Motion Question 16 – UPSC CDS/OTA