Circular Motion · UPSC CDS/OTA · Question 13 of 30

Circular Motion – Question 13

Step-by-step solution. Circular Motion for UPSC CDS/OTA.

Topic
Circular Motion
Subject
General Studies
Difficulty
Medium
Solve Time
45–60 sec

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Q · Circular MotionMedium · 45s

A particle completes 5 revolutions in 2 seconds. What is its angular speed?

TopicCircular Motion
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min

Step-by-Step Solution

The complete worked solution.

Every step explained — no skipped algebra.

1 revolution = 2π rad ⇒ 5 revolutions = 10π rad; so, ω = 10π/2 = 5π rad/s.

Final Answer: Option B — 10π10π rad/s
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Circular Motion Question 13 – UPSC CDS/OTA