Solved UPSC CDS/OTA Question
A solved UPSC CDS/OTA PYQ - decoded step-by-step.
Solve it the standard way once - then learn the shortcut.
Q · Average Medium · 45s
The average of four positive integers is 73.5. The highest integer is 108 and the least integer is 29. The difference between the remaining two integers is 15. Which of the following is smaller of the remaining two integers?
TopicAverage
Question Typemultiple choice
DifficultyMedium
Marking+1 / −0.33
Test Duration30 min
Step-by-Step Solution
The complete worked solution.
Every step explained - no skipped algebra.
Sum of 4 integers = 72.5 × 4 = 294
Sum of the remaining two integers
= 294 – (108 + 29) = 157
If remaining two integers be x and y, then
x + y = 157 and x – y = 15
Solving these equations, we get
x = 86, y = 71
∴ Small integer = 71
Final Answer: Option B - 71